169p^2=16

Solution for 169p^2=16 equation:

169p^2=16

We move all terms to the left:

169p^2-(16)=0

a = 169; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·169·(-16)
Δ = 10816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10816}=104$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-104}{2*169}=\frac{-104}{338}
=-4/13
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+104}{2*169}=\frac{104}{338}
=4/13
$